prob5-13 (team 1)

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5-13: assuming that the reaction of the ground to be uniformaly distributed draw the shear and bending-moment diagram for the bean AB and determine the maximum absolute value (a) of the shear (b) of the bending -moment.

Image(178).jpg
solution:
Fy=0
1.5+1.5-Ra-Rb=0
Ma=0
(-1.5*0.3)+(1.5*1.2)-(Rb*1.5)=0 1.5(Rb)=1.35 Rb=0.9 Ra=2.1

Image(182).jpg
Fy=0
S1= 2.1 kn
M1=0 M-2.1(X)=0
M1=2.1X



Fy=0
S2+1.5-2.1=0 S2=0.6
M2=0
-2.1X+1.5(X-0.3)+M=0 -0.6X-0.45=-M M2=0.45+0.6XImage(183).jpg


Fy=0
S3+1.5+1.5-2.1=0 S3=-0.9

M3=0
-2.1X+1.5(X-0.3)-1.5(x-1.2)+M=0 M3=2.1X-1.35Image(179).jpgImage(184).jpg