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6-13
:
two steels plates of 12*220- mm rectangular cross section are welded to the w250* 58 beam as shown . determine the largest allowble vertical shear if the shearing stress in the beam is not exceed 90 MPa
solution
:
I=2(8*225^3*10^-12/12)+2((203*13.5^3*10^-12/12)+(13.5*203*10^-6)(119.25*10^-3)^2)+2((220*12^3*10^-12/12)+(12*220*10^-6)(132*10^-3)^2)
I=(1.51875*10^-5)+(7.8023*10^-5)+(9.204*10^-5)
I=1.8525*10^-4
Q=A*Y'
Q= 132*10^-3*220*12*10^-6
Q=3.4848*10^-4
S=10525.56 KN
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I=2(8*225^3*10^-12/12)+2((203*13.5^3*10^-12/12)+(13.5*203*10^-6)(119.25*10^-3)^2)+2((220*12^3*10^-12/12)+(12*220*10^-6)(132*10^-3)^2)
I=(1.51875*10^-5)+(7.8023*10^-5)+(9.204*10^-5)
I=1.8525*10^-4
Q=A*Y'
Q= 132*10^-3*220*12*10^-6
Q=3.4848*10^-4
S=10525.56 KN