7-37 :solve prob 7-15 using mohr's circle
Image(217).jpg

solution:

stress(X)= -60 MPA
stress(Y)= 90 MPA
txy= 30 MPA


stress(AVG)=C=(oy+ox)/2=(90-60)/2=15 MPA

cy=oy-oc=90-15=75
tan2$=(yk/cy)=(30/75)

$=10.9
R=sqrt(ky^2+cy^2) = 80.77
first: anti clockwise (10 degrees)

cos@=(cx'/R)
cx'=80.77*cos 41.8
cx'=60.21 MPA
cx'=ox'+oc
stress(X')=oX'=60.21-15
=45.2 MPA




second: with colckwise(25 degress):
cos#=(cx'/R)
cx'=80.77*cos28.4
=71.049 MPA
cx'=71.049
ox'=cx'-oc
=71.049-15
=- 56.049 MPA