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7.87:the 36-mm diamater shaftis made of a grade of steel with a 250-MPA tensile yield stress. using the max- sheraing -stress critrion.determinethe magnitude of the torque Tfoe which yield occurs when P=200 KN
solution:
Tmax=0.5*yield stress
=0.5*250
=125 MPA
Tmax=(T*C/J)
stress(y)=(-p/A)=(-200*10^-3)/((3.14/4)(.036^2))
stress(y)=-196.487 MPA
C=(stressy/2)=-98.2435
Txy^2=Tmax^2-(stressy-C)
Txy^2=(125)^2-(89.2435)^2
Txy=77.286 MPA
T=708 N.m
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Tmax=0.5*yield stress
=0.5*250
=125 MPA
Tmax=(T*C/J)
stress(y)=(-p/A)=(-200*10^-3)/((3.14/4)(.036^2))
stress(y)=-196.487 MPA
C=(stressy/2)=-98.2435
Txy^2=Tmax^2-(stressy-C)
Txy^2=(125)^2-(89.2435)^2
Txy=77.286 MPA
T=708 N.m