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prob7.104 (team1) edited 7.104: the unpressurized clyindirical storage tank shown has a 5-mm wall thickness and is made of …

7.104: the unpressurized clyindirical storage tank shown has a 5-mm wall thickness and is made of steel having a 420-MPA ultimate strength in tension determine the maximum height h to which it can be filled with water if a factoe of safety 4.0 (specific weight of water is 9810 N/M^3
solution:
t= 5 mm
f.c.=4.0
ultimate strengh=420 MPA
f.c.=(ult/stress h)
stress hoop=
(420/4)=105 MPA
volume of clyinder=(3.14/4)(7.5)^2*15=662.67 m^3
weight of water= 9810*662.67=6500887.861 N
Fh=stress(h)*h*2*t
h=(650088.81/105*10^6*5*2)
h=6.19 m

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prob7.87 (team1) edited 7.87:the 36-mm diamater shaftis made of a grade of steel with a 250-MPA tensile yield stress. usin…

7.87:the 36-mm diamater shaftis made of a grade of steel with a 250-MPA tensile yield stress. using the max- sheraing -stress critrion.determinethe magnitude of the torque Tfoe which yield occurs when P=200 KN
{Image(001).jpg} solution:
Tmax=0.5*yield stress
=0.5*250
=125 MPA
Tmax=(T*C/J)
stress(y)=(-p/A)=(-200*10^-3)/((3.14/4)(.036^2))
stress(y)=-196.487 MPA
C=(stressy/2)=-98.2435
Txy^2=Tmax^2-(stressy-C)
Txy^2=(125)^2-(89.2435)^2
Txy=77.286 MPA
T=708 N.m

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Image(001).jpg uploaded

prob7.85 (team1) edited 7.85: the 44-mm diamater shaft AB is made of a grade of steel for which the yield strength is stre…

7.85: the 44-mm diamater shaft AB is made of a grade of steel for which the yield strength is stress yield= 250 MPA using the maximum-shearing -stress-criterion .determine the magnitude of the force P for yield occurs when T=1.5 KN.m.
{Image.jpg} solution:
stress(y)=0
stress(x)=P/A
Txy=(Tc/J)
Txy=(1.5*1000*22*10^-3/0.5*3.14*(22*10^-3)^4)
=89.68 MPA
Tmax=0.5*stress yield=0.5*250 = 125 MPA
(Tmax)^2=(Txy)^2+(stressx-c)
(125)^2-(89.68)^2=0.5*stressx
stress x=174.155 MPA
P=stressx *A
P=174.155*10^6*(3.14/4)(.044)^2
P=264.8 KN

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Image.jpg uploaded

prob7-49 (team1) edited 7-49 :solve problem 7.27 usnig mohr's circle {Image(218).jpg} solution: cy=sqrt(ac^2-ay^2) cy=s…

7-49 :solve problem 7.27 usnig mohr's circle
{Image(218).jpg} solution:
cy=sqrt(ac^2-ay^2)
cy=sqrt(75^2-20^2)
=72.28 MPA
oy=(2*cy)+ox
oy=(2*72.28)+60
oy=stress lareger value of Y=205 MPA

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Image(218).jpg uploaded

prob7-5 (team1) (deleted) edited

prob7-37 (team1) edited (view changes)

prob7-37 (team1) edited 7-37 :solve prob 7-15 using mohr's circle {Image(217).jpg} solution: stress(X)= -60 MPA stres…

7-37 :solve prob 7-15 using mohr's circle
{Image(217).jpg}
solution:
stress(X)= -60 MPA
stress(Y)= 90 MPA
txy= 30 MPA
stress(AVG)=C=(oy+ox)/2=(90-60)/2=15 MPA
cy=oy-oc=90-15=75
tan2$=(yk/cy)=(30/75)
$=10.9
R=sqrt(ky^2+cy^2) = 80.77
first: anti clockwise (10 degrees)
cos@=(cx'/R)
cx'=80.77*cos 41.8
cx'=60.21 MPA
cx'=ox'+oc
stress(X')=oX'=60.21-15
=45.2 MPA
second: with colckwise(25 degress):
cos#=(cx'/R)
cx'=80.77*cos28.4
=71.049 MPA
cx'=71.049
ox'=cx'-oc
=71.049-15
=- 56.049 MPA

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